l = Lower limit of the median class,
h = width of the median class,
f = frequency of the median class
c = cumulative frequency of the class preceding the
median class
n = total frequency
Problem: Calculate the median days of maturity of 40-short term investments.
Table: 8
Class interval
|
Frequency
(fi)
|
Cumulative
frequency
|
30—39
|
3
|
3
|
40—49
|
1
|
4
|
50—59
|
8
|
12
|
60—69
|
10
|
22
|
70—79
|
7
|
29
|
80—89
|
7
|
36
|
90—99
|
4
|
40
|
Total
|
40
|
|
If we use the above equation to compute the median of data of days to maturity 40 short-term investments in Table 8, then n/2 = 20, median class is 60-69, l = 60, h = 10, f = 10, c = 12. Then
Mode: The mode, if one exists, is the most frequently occurring value.
Example: The demand for bottled water increases during the hurricane season in Florida. A random sample of 7 hours showed that the following numbers of 1-gallon bottles were sold in one store:
40 43 62 43 50 60 65
The mode is 43 bottles, since it occurs twice and all the other number of bottles occur only once. However, the mode in this case is the smallest value and is not the best indicator of central tendency. If the sample included a eighth hour number of bottles of 65:
40 43 43 50 60 62 65 65
we see that the data are bimodal, which modes are 43 and 65.
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